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Consider the given ions and their number of unpaired electrons. The correct order is

$\begin{array}{1 1} Fe^{2-} > Mn^{2+} > Cr^{2+} > C0^{2+} \\ Co^{2+} > Mn^{2+} > Cr^{2+} > Fe^{2+} \\ Fe^{2-} < Mn^{2+} > Cr^{2+} > C0^{2+} \\Mn^{2+} > Fe^{2+} = Cr^{2+} > C0^{2+} \end{array} $

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