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Home  >>  EAMCET  >>  Chemistry
0 votes

In the reaction

 the change in the oxidation state of vanadium is from $V^{5+}$ to

$\begin {array} {1 1} (1)\;V^{4+} & \quad (2)\;V^{6+} \\ (3)\;V^{3+} & \quad (4)\;V^{2+} \end {array}$

 

Can you answer this question?
 
 

1 Answer

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(1) $ V^{4+}$
answered Nov 7, 2013 by pady_1
 
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