Browse Questions

# In the reaction

the change in the oxidation state of vanadium is from $V^{5+}$ to

$\begin {array} {1 1} (1)\;V^{4+} & \quad (2)\;V^{6+} \\ (3)\;V^{3+} & \quad (4)\;V^{2+} \end {array}$

(1) $V^{4+}$