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Calculate $\Delta H$ in kJ for the following reaction : $C_{(s)}+O_{2(g)} \longrightarrow CO_{2(g)}$ Given that , \[ H_2 O_{(g)} + C_{(s)} \longrightarrow CO_{(g)} + H_{2(g)} +H_{2(g)} \quad \Delta H =+131\;kJ\] \[CO_{(g)}+\large\frac{1}{2} O_{2(g)} \longrightarrow CO_{2(g)} \qquad \Delta H =-282\;kJ\] \[H_{2(g)}+\frac{1}{2} \;O_{2(g)} \longrightarrow H_2O_{(g)} \qquad \Delta H =-242\;kJ\]

\[\begin {array} {1 1} (1)\;-393 & \quad (2)\;+393 \\ (3)\;+655 & \quad (4)\;-655 \end {array}\]
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(1) -393
answered Nov 7, 2013 by pady_1

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