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An object of mass 2m is projected with a speed of $100\;ms^{1}$ at an angle $\theta=\sin ^{-1} \bigg(\large\frac{3}{5}\bigg)$ to the horizontal. At the highest point, the object breaks into two pieces of same mass m and the first one comes to rest. The distance between the point of projection and the point of landing of the bigger piece (in meter) is (Given , $g= 10 m/s^2$)

\[\begin {array} {1 1} (a)\;3840 & \quad (b)\;1280 \\ (c)\;1440 & \quad (d)\;960 \end {array}\]

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(3) 1440
answered Nov 7, 2013 by pady_1

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