An object of mass 2m is projected with a speed of $100\;ms^{1}$ at an angle $\theta=\sin ^{-1} \bigg(\large\frac{3}{5}\bigg)$ to the horizontal. At the highest point, the object breaks into two pieces of same mass m and the first one comes to rest. The distance between the point of projection and the point of landing of the bigger piece (in meter) is (Given , $g= 10 m/s^2$) - Clay6.com, a Free resource for your JEE, AIPMT and Board Exam preparation

An object of mass 2m is projected with a speed of $100\;ms^{1}$ at an angle $\theta=\sin ^{-1} \bigg(\large\frac{3}{5}\bigg)$ to the horizontal. At the highest point, the object breaks into two pieces of same mass m and the first one comes to rest. The distance between the point of projection and the point of landing of the bigger piece (in meter) is (Given , $g= 10 m/s^2$)