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In two separate collisions, the coefficient of restitutions $e_1$ and $e_2$ are in the ratio $3:1$ . In the first collision the relative velocity of approach is twice the relative velocity of separation, then the ratio between relative velocity of approach and the relative velocity of separation in the second collision is

\[\begin {array} {1 1} (a)\;1:6 & \quad (b)\;2:3 \\ (c)\;3:2 & \quad (d)\;6:1 \end {array}\]
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(4) 6:1
answered Nov 7, 2013 by pady_1

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