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A black body radiates energy at the rate of $E watt/m^2$ at a high temperature T K. When the temperature is reduced to $\bigg(\large\frac{T}{2}\bigg)$K, the radiant energy is

\[\begin {array} {1 1} (a)\;\frac{E}{2} & \quad (b)\;2E \\ (c)\;\frac{E}{4} & \quad (d)\;\frac{E}{16}\end {array}\]
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$ (d)\;\frac{E}{16}$
answered Nov 7, 2013 by pady_1

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