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A segment of wire vibrates with a fundamental frequency of $450\;Hz$ under a tension of 9 Kg wt. Then tension at which the fundamental frequency of the same wire becomes 900 Hz is

\[\begin {array} {1 1} (a)\;36\;kg-wt & \quad (b)\;27\;kg-wt \\ (c)\;18 kg-wt & \quad (d)\;72\;kg-wt \end {array}\]

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(a) 36 kg -wt
answered Nov 7, 2013 by pady_1

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