Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

How many molecules of atoms of oxygen are present in 5.6litres of oxygen $(O_2)$ at NTP?

$\begin{array}{1 1}(a)\;3.01\times 10^{23}atoms&(b)\;2\times 10^{23}atoms\\(c)\;1.9\times 10^{23}atoms&(d)\;4\times 10^{23}atoms\end{array}$

Can you answer this question?

1 Answer

0 votes
We know that 22.4litres of oxygen at NTP contain $6.02\times 10^{23}$ molecules of oxygen.
So,5.6litres of oxygen at NTP contain=$\large\frac{5.6}{22.4}$$\times 6.02\times 10^{23}$ molecules.
$\Rightarrow 1.505\times 10^{23}$ molecules.
1 molecule of oxygen contain =2 atoms of oxygen
So,$1.505\times 10^{23}$ molecules of oxygen contain=$2\times 1.505\times 10^{23}atom$
$\Rightarrow 3.01\times 10^{23}atom$
Hence (a) is the correct answer.
answered Oct 23, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App