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How many electrons are present in 1.6g of methane?

$\begin{array}{1 1}(a)\;6.02\times 10^{22}&(b)\;6.02\times 10^{23}\\(c)\;6.02\times 10^{20}&(d)\;7.5\times 10^{23}\end{array}$

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1 Answer

Gram-molecular mass of methane ($CH_4)=12+4=16g$
Number of moles in 1.6g of methane =$\large\frac{1.6}{16}=$$0.1$
Number of molecules of methane in 0.1mole=$0.1\times 6.02\times 10^{23}$
$\Rightarrow 6.02\times 10^{22}$
One molecules of methane has $6+4=10$electrons
So,$6.02\times 10^{23}$ molecules of methane have $=10\times 6.02\times 10^{22}$electrons
$\Rightarrow 6.02\times 10^{23}$ electrons
Hence (b) is the correct answer.
answered Oct 23, 2013 by sreemathi.v
 

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