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The electric charge on the electron is $1.602\times 10^{-19}$ coulomb.How much charge is present on 0.1 mole of $Cu^{2+}$ ions?

$\begin{array}{1 1}(a)\;1\;Faraday&(b)\;2\;Faraday\\(c)\;0.5\;Faraday&(d)\;0.2\;Faraday\end{array}$

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Charge on one mole of electrons $=6.02\times 10^{23}\times 1.602\times 10^{-19}$coulomb
$\Rightarrow 96500C=1Faraday$
Charge on one mole of $Cu^{2+}$ ions=$2\times 96500C$
$\Rightarrow 2$ Faraday
$\therefore$ Charge on 0.1mole of $Cu^{2+}$ ions=$0.1\times 2$
$\Rightarrow 0.2$ Faraday
Hence (d) is the correct answer.
answered Oct 23, 2013 by sreemathi.v

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