$\begin{array}{1 1}(a)\;2E\big(\large\frac{y}{x}\big)&(b)\;xyE\\(c)\;\large\frac{E}{y}&(d)\;\large\frac{y}{E}\end{array}$

Let atomic mass of metal m is $'a'$

Mass of metal =$a\times x$

Mass of oxygen $=16\times y$

Equivalent mass of element =$\large\frac{Mass\;of\;element}{Mass\;of\;oxygen}$$\times 8$

$E=\large\frac{ax}{16y}$$\times 8$

$\Rightarrow a=2E\big(\large\frac{y}{x}\big)$

Hence (a) is the correct answer.

why did you multiply by 8 dude

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