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A metal m of equivalent mass E forms an oxide of molecular formula $M_xO_y$ .The atomic mass of the metal is given by the correct equation.

$\begin{array}{1 1}(a)\;2E\big(\large\frac{y}{x}\big)&(b)\;xyE\\(c)\;\large\frac{E}{y}&(d)\;\large\frac{y}{E}\end{array}$

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