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The equivalent weight of a metal is double than that of oxygen .How many times is the weight of its oxide greater than the weight of metal?

$(a)\;4\qquad(b)\;2\qquad(c)\;3\qquad(d)\;1.5$

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Equivalent mass of metal =16=$\large\frac{x}{n}$
Equivalent mass of oxygen is 8
When $x$=atomic mass of metal
$\qquad n$=valency of metal
Molecular formula of metal oxide $=M_xO_n$
$\large\frac{mass\;of\;metal\;oxide}{mass\;of\;metal}=\frac{2(16 n)+16(n)}{2(16n)}$
$\Rightarrow 1.5$
Hence (d) is the correct answer.
answered Oct 23, 2013 by sreemathi.v
 

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