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A chloride of an element contains 49.5% chlorine.The specific heat of the element is $0.056$.Calcuate the equivalent mass,valency.

$(a)\;2,35\qquad(b)\;3,36.21\qquad(c)\;4,37.21\qquad(d)\;1,35.12$

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Mass of chlorine in the metal chloride =49.5%
Mass of metal =(100-49.5)=50.5
Equivalent mass of the metal =$\large\frac{mass\;of\;metal}{mass\;of\;chlorine}$$\times 35.5$
$\qquad\qquad\qquad\qquad\qquad=\large\frac{50.5}{49.5}$$\times 35.5$
$\qquad\qquad\qquad\qquad\qquad=36.21$
According to Dulong and Petit's law
Atomic mass of the metal =$\large\frac{6.4}{specific\;heat}$
$\qquad\qquad\qquad\qquad\quad=\large\frac{6.4}{0.056}$$\times 114.3$
$\therefore$ valency =$\large\frac{Approx.atomic\;mass}{Equivalent\; mass}$
$\qquad\qquad=\large\frac{114.3}{36.21}$
$\qquad\qquad=3.1$
$\qquad\qquad=3$(approx)
Hence (b) is the correct answer.
answered Oct 23, 2013 by sreemathi.v
edited Oct 23, 2013 by sreemathi.v
 

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