$(a)\;2,35\qquad(b)\;3,36.21\qquad(c)\;4,37.21\qquad(d)\;1,35.12$

Mass of chlorine in the metal chloride =49.5%

Mass of metal =(100-49.5)=50.5

Equivalent mass of the metal =$\large\frac{mass\;of\;metal}{mass\;of\;chlorine}$$\times 35.5$

$\qquad\qquad\qquad\qquad\qquad=\large\frac{50.5}{49.5}$$\times 35.5$

$\qquad\qquad\qquad\qquad\qquad=36.21$

According to Dulong and Petit's law

Atomic mass of the metal =$\large\frac{6.4}{specific\;heat}$

$\qquad\qquad\qquad\qquad\quad=\large\frac{6.4}{0.056}$$\times 114.3$

$\therefore$ valency =$\large\frac{Approx.atomic\;mass}{Equivalent\; mass}$

$\qquad\qquad=\large\frac{114.3}{36.21}$

$\qquad\qquad=3.1$

$\qquad\qquad=3$(approx)

Hence (b) is the correct answer.

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