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On dissolving 2.0g of metal in sulphuric acid 4.51g of the metal sulphate was formed.The specific heat of the metal is 0.057cal/g.What is the exact atomic mass of the metal?


1 Answer

Step 1:
Equivalent mass of $SO_4^{2-}$ radical $=\large\frac{Ionic\;mass}{Valency}$
Mass of metal sulphate=4.51g
Mass of metal=2.0g
Mass of sulphate metal =4.51-2.0=2.51g
2.51g of sulphate combine with 2.0g of metal
So,48g of sulphate will combine with =$\large\frac{2}{2.51}$$\times 48$
$\Rightarrow 38.24g$ metal
Equivalent mass of metal=38.24
Step 2:
According to Dulong and Petit's law
Approximate atomic mass=$\large\frac{6.4}{specific\;heat}$
Valency =$\large\frac{(Approx)atomic\; mass}{Equivalent\;mass}$
Step 3:
$\therefore$ Exact atomic mass=$38.24\times 3$
$\Rightarrow 114.72$
Hence (b) is the correct answer.


answered Oct 23, 2013 by sreemathi.v
edited Jan 15 by sharmaaparna1

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