Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

On dissolving 2.0g of metal in sulphuric acid 4.51g of the metal sulphate was formed.The specific heat of the metal is 0.057cal/g.What is the exact atomic mass of the metal?


Can you answer this question?

1 Answer

0 votes
Step 1:
Equivalent mass of $SO_4^{2-}$ radical $=\large\frac{Tonic\;mass}{Valency}$
Mass of metal sulphate=4.51g
Mass of metal=2.0g
Mass of sulphate metal =4.51-2.0=2.51g
2.51g of sulphate combine with 2.0g of metal
So,48g of sulphate will combine with =$\large\frac{2}{2.51}$$\times 48$
$\Rightarrow 38.24g$ metal
Equivalent mass of metal=38.24
Step 2:
According to Dulong and Petit's law
Approximate atomic mass=$\large\frac{6.4}{specific\;heat}$
Valency =$\large\frac{(Approx)atomic\; mass}{Equivalent\;mass}$
Step 3:
$\therefore$ Exact atomic mass=$38.24\times 3$
$\Rightarrow 114.72$
Hence (b) is the correct answer.
answered Oct 23, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App