$\begin{array}{1 1}(a)\;Mcl_3&(b)\;Mcl_2\\(c)\;Mcl_4&(d)\;Mcl\end{array}$

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Mass of metal chloride =1g

Mass of chlorine =0.835g

Mass of metal =1-0.835

$\qquad\qquad\;\;\;=0.165$g

Equivalent mass of metal =$\large\frac{0.165}{0.835}$$\times 35.5$

$\qquad\qquad\qquad\quad\quad\;\;\;=7.01$

We know that

Valency of metal =$\large\frac{2\times vapour \;density}{E+35.5}$

$\qquad\qquad\qquad=\large\frac{2\times 85}{7.01+35.5}$

$\qquad\qquad\qquad=4$

Formula of the metal chloride =$Mcl_4$

Hence (c) is the correct option.

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