Email
Chat with tutors
logo

Ask Questions, Get Answers

X
 
Answer
Comment
Share
Q)

Vertices of hyperbola are x^2-6y^2+4x+12y+1 are

Vertices of hyperbola are x^2-6y^2+4x+12y+1 are

Please log in or register to answer this question.

Home Ask Tuition Questions
Your payment for is successful.
Continue
...