$(a)\;16\qquad(b)\;15.28\qquad(c)\;17.1\qquad(d)\;14$

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Mass of element $=32.33$parts

Mass of oxygen =$100-32.33$

$\Rightarrow 67.67$

Equivalent mass of the element =$\large\frac{32.33}{67.67}$$\times 8$

$\qquad\qquad\qquad\qquad\qquad\quad=3.82$

Valency of the element =$\large\frac{2\times vapor\;density}{E+35.5}$

$\Rightarrow \large\frac{2\times 79}{3.82+35.5}$

$\Rightarrow 4$

Hence the atomic mass of the element =$3.82\times 4$

$\qquad\qquad\qquad\qquad\qquad\qquad\quad=15.28$

Hence (b) is the correct answer.

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