$(a)\;80\qquad(b)\;65\qquad(c)\;75\qquad(d)\;95$

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The molecular mass of pure sodium chloride (Nacl)=At mass of Na+At mass of chloride

$\Rightarrow (23+35.5)$

$\Rightarrow 58.5$

% of chlorine in pure Nacl=$\large\frac{35.5}{58.4}$$\times 100=60.6$

Thus % of purity of Nacl in the sample=$\large\frac{45.5}{60.6}$$\times 100$

$\Rightarrow 75$

Hence (c) is the correct answer.

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