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The decreasing order of bond dissociation energies of C - C, C -H and H -H bound is

\[\begin {array} {1 1} (a)\;H-H > -C-H > -C-C- & \quad (b)\;-C-C- > C-H > H-H \\ (c)\;-C-H- > -C-C- > H-H & \quad (d)\;-C-C- > H-H > -C-H \end {array}\]

1 Answer

$(a)\;H-H > -C-H > -C-C-$
answered Nov 7, 2013 by pady_1
 

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