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# Calculate the empirical formula for a compound that contains 26.6% potassium,35.4% chromium and 38.1% oxygen.(Given :K=39.1,Cr=52,O=16)

$\begin{array}{1 1}(a)\;K_3Cr_2O_3&(b)\;K_2Cr_2O_7\\(c)\;KCr_2O_6&(d)\;KCr_3O_8\end{array}$

Therefore,empirical formula is $K_2Cr_2O_7$
Hence (b) is the correct answer.