Calculate the emf of the cell $Cu(s)|Cu^{2+} (aq)| |Ag^{+}(aq)| Ag(s)$ Given $E^{\circ}_{Cu^{2+}/Cu} =+0.34 \;V, E^{\circ}_{Ag^{+}/Ag}=0.80\;V$

$\begin {array} {1 1} (a)\;+0.46\; V & \quad (b)\;+1.14\;V \\ (c)\;+0.57\;V & \quad (d)\;-0.46\;V \end {array}$

$(a)\;+0.46\; V$
answered Nov 7, 2013 by