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Calculate the emf of the cell $ Cu(s)|Cu^{2+} (aq)| |Ag^{+}(aq)| Ag(s) $ Given $E^{\circ}_{Cu^{2+}/Cu} =+0.34 \;V, E^{\circ}_{Ag^{+}/Ag}=0.80\;V$

\[\begin {array} {1 1} (a)\;+0.46\; V & \quad (b)\;+1.14\;V \\ (c)\;+0.57\;V & \quad (d)\;-0.46\;V \end {array}\]

1 Answer

$(a)\;+0.46\; V$
answered Nov 7, 2013 by pady_1
 

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