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Q)

An organic compound containing C and it has 92.3% carbon .Its empirical formula is :

$\begin{array}{1 1}(a)\;CH&(b)\;CH_3\\(c)\;CH_2&(d)\;CH_4\end{array}$

2 Answers

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A)
Empirical formula=CH
Hence (a) is the correct option
A. CH is correct answer..
 
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A)
We have, C=92.3% = 92.3/12=7.6 H=100-92.3=7.7
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