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Two oxides of a metal contain 50% and 40% of metal M respectively.If the formula of first oxide is MO,+ve formula of $2^{nd}$ oxide will be

$\begin{array}{1 1}(a)\;MO_2&(b)\;M_2O_3\\(c)\;M_2O&(d)\;M_2O_5\end{array}$

Can you answer this question?
 
 

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Formula =$MO$
Formula =$M_2O_3$
Hence (b) is the correct answer.
answered Oct 24, 2013 by sreemathi.v
 

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