Browse Questions

Weight of oxygen in $Fe_2O_3$ and FeO in the simple ratio for the same amount of Fe is

$(a)\;1 : 2\qquad(b)\; 2 :1\qquad(c)\;3 : 2\qquad(d)\;1 : 3$

Ratios 112 : 48,56 : 16
$\therefore$ Simple ratio for O for same amount of Fe is 48 : 32
(i.e) 3 : 2
Hence (c) is the correct answer.