$\begin{array}{1 1}(a)\;8.30\times 10^{-23}g&(b)\;2.08\times 10^{-23}g\\(c)\;5.53\times 10^{-23}g&(d)\;6.24\times 10^{-23}g\end{array}$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

$PV=nRT$

$\therefore PV=\large\frac{U}{m}$$RT$

$\Rightarrow \large\frac{1}{m}$$\times 0.0821\times 273$

$\therefore m=100$

$3N$ atoms of gas weighs 100g

$\therefore$ 1 atom of gas weighs =$\large\frac{100}{3\times 6.023\times 10^{23}}$

$\Rightarrow 5.53\times 10^{-23}g$

Hence (c) is the correct answer.

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...