Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

224 ml of triatomic gas weights 1g at 173k and 1atm .The mass of one atom of this gas is

$\begin{array}{1 1}(a)\;8.30\times 10^{-23}g&(b)\;2.08\times 10^{-23}g\\(c)\;5.53\times 10^{-23}g&(d)\;6.24\times 10^{-23}g\end{array}$

Can you answer this question?

1 Answer

0 votes
$\therefore PV=\large\frac{U}{m}$$RT$
$\Rightarrow \large\frac{1}{m}$$\times 0.0821\times 273$
$\therefore m=100$
$3N$ atoms of gas weighs 100g
$\therefore$ 1 atom of gas weighs =$\large\frac{100}{3\times 6.023\times 10^{23}}$
$\Rightarrow 5.53\times 10^{-23}g$
Hence (c) is the correct answer.
answered Oct 24, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App