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# If $R \to R$ and $g: R \to R$ are defined by $f(x)=x-[x]$ and $g(x)=[x]$ for $x \in R,$ where $[x]$ is the greatest integer not exceeding x, then for every $x \in R, f(g(x))$ is equal to

$\begin {array} {1 1} (a)\;x & \quad (b)\;0 \\ (c)\;f(x) & \quad (d)\;g(x) \end {array}$

(b) 0