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The number of ways of arranging 8 men and 4 women around a circular table such that no two women can sit together is

\[\begin {array} {1 1} (a)\;8 ! & \quad (b)\;4 ! \\ (c)\;8 ! 4 ! & \quad (d)\;7 ! \; ^SP_4 \end {array}\]

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1 Answer

$(d) 7 ! ^SP_4$
answered Nov 7, 2013 by pady_1
 

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