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If $\large\frac{3x}{(x-a)(x-b)}=\frac{2}{x-a}+\frac{1}{x-b}$ then $a:b$ is equal to

\[\begin {array} {1 1} (a)\;1:2 & \quad (b)\;-2:1 \\ (c)\;1:3 & \quad (d)\;3:1 \end {array}\]
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1 Answer

(b) -2:1
answered Nov 7, 2013 by pady_1
 

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