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If $\cos (A-B)=3/5$ and $\tan A \tan B=2$. then which one of the following is true?

\[\begin {array} {1 1} (a)\;\sin (A+B)=\frac{1}{5} & \quad (b)\;\sin (A+B)=-\frac{1}{5} \\ (c)\;\cos (A-B)=\frac{1}{5} & \quad (d)\;\cos (A+B)=-\frac{1}{5} \end {array}\]

1 Answer

$(d)\;\cos (A+B)=-\frac{1}{5} $
answered Nov 7, 2013 by pady_1
 
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