logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

In the first world war ,$1.1\times 10^8$kg of position gas were fired on the allied forces.If the gas is assumed to be phosgene,how many molecules of the gas correspond to the amount fired on allied forces.

$\begin{array}{1 1}(a)\;1.9\times 10^{-15}&(b)\;6.7\times 10^{32}\\(c)\;2.9\times 10^{-15}&(d)\;6.7\times 10^{29}\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
Phosgene is $COCl_2$(mol.wt =99)
$99g$=Nmolecules
$\therefore 1.1\times 10^{11}g=\large\frac{N\times 1.1\times 10^{11}}{99}$
$\Rightarrow 6.7\times 10^{32}$
Hence (b) is the correct answer.
answered Oct 25, 2013 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...