Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XII  >>  Math  >>  Three Dimensional Geometry
0 votes

Find the equation of the plane with intercept 3 on the y - axis and parallel to ZOX plane.

$\begin{array}{1 1} x=3 \\y=3 \\z=3 \\ x+y+x=3\end{array} $

Can you answer this question?

1 Answer

0 votes
  • Equation of a plane,whose intercepts are $a,b,c$ is given by $\large\frac{x}{a}$$+\large\frac{y}{b}$$+\large\frac{z}{c}$$=1$
Step 1:
We know that the equation of the plane $ZOX$ is $y=0$
Any plane which is parallel to it is of the form $y=a$
Where $a$ is the $y$-intercept of the plane.
Step 2:
But it is given $a=3$
Therefore the equation of the required plane is $y=3$
answered May 30, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App