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A partially dried clay mineral contains 8% water.The original sample contained 12% water and 45% silica.The % of silica in the partially dried sample in nearly :

$(a)\;50\%\qquad(b)\;49\%\qquad(c)\;55\%\qquad(d)\;47\%$

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The % ratio of silica and clay remains constant an heating
(i.e) $\large\frac{45}{43}=\frac{a}{92-a}$
$\Rightarrow a=47$%
Hence (d) is the correct answer.
answered Oct 25, 2013 by sreemathi.v
 

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