Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

When the same amount of zinc is treated separately with excess of $H_2SO_4$ and excess of $NaOH$,the ratio of volumes of $H_2$ evolved is

$(a)\; 1 : 1\qquad(b)\;1 : 2\qquad(c)\;2 : 1\qquad(d)\;9 : 4$

Can you answer this question?

1 Answer

0 votes
$Zn+H_2SO_4\rightarrow ZnSO_4+H_2$
$Zn+2NaOH\rightarrow Na_2ZnO_2+H_2$
$\therefore $ratio of volumes of $H_2$ evolved is 1 : 1
Hence (a) is the correct answer.
answered Oct 25, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App