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Four numbers are chosen at random from {1,2,3............,40}. The probability that they are not consecutive, is

\[\begin {array} {1 1} (a)\;\frac{1}{2470} & \quad (b)\;\frac{4}{7969} \\ (c)\;\frac{2469}{2470} & \quad (d)\;\frac{7965}{7969} \end {array}\]

1 Answer

$(c) \frac{2469}{2470}$
answered Nov 7, 2013 by pady_1
 

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