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Four numbers are chosen at random from {1,2,3............,40}. The probability that they are not consecutive, is
\[\begin {array} {1 1} (a)\;\frac{1}{2470} & \quad (b)\;\frac{4}{7969} \\ (c)\;\frac{2469}{2470} & \quad (d)\;\frac{7965}{7969} \end {array}\]
jeemain
eamcet
math
2007
q40
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Oct 25, 2013
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meena.p
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1 Answer
$(c) \frac{2469}{2470}$
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Nov 7, 2013
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pady_1
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