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Home  >>  EAMCET  >>  Mathematics
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If A and B are mutually exclusive events with $P(B) \neq 1,$ then $P(A | \bar {B})$ is equal to (Here $\bar B$ is the complement of the event B)

\[\begin {array} {1 1} (a)\;\frac{1}{P(B)} & \quad (b)\; \frac{1}{1-P(B)} \\ (c)\;\frac{P(A)}{P(B)} & \quad (d)\; \frac{P(A)}{1-P(B)} \end {array}\]
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$ (d)\; \frac{P(A)}{1-P(B)} $
answered Nov 7, 2013 by pady_1
 

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