Browse Questions

# The mean and standard deviation of a binomial variate x are 4 and $\sqrt 3$ respectively. Then $P( X \geq 1)$ is equal to

$\begin {array} {1 1} (a)\;1-\bigg(\frac{1}{4}\bigg)^{16} & \quad (b)\;1-\bigg(\frac{3}{4}\bigg)^{16} \\ (c)\;1-\bigg(\frac{2}{3}\bigg)^{16} & \quad (d)\;1-\bigg(\frac{1}{3}\bigg)^{16} \end {array}$

$(b)\;1-\bigg(\frac{3}{4}\bigg)^{16}$