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If 2∫10tan^−1xdx=∫10cot^−1(1−x+x^2)dx, then ∫10tan^−1(1−x+x
If 2∫10tan^−1xdx=∫10cot^−1(1−x+x^2)dx, then ∫10tan^−1(1−x+x^2)dx is equal to: (a)log 4 (b)π/2+log2 (c)log 2 (d)π/2−log4
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