Browse Questions

# The inverse point of (1,2) with respect to the circle $x^2+y^2-4x-6y+9=0$ is

$\begin {array} {1 1} (a)\;(0,0) & \quad (b)\;(1,0) \\ (c)\;(0,1) & \quad (d)\;(1,1) \end {array}$

(c) (0,1)