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# The circumference of a circle is measured as 56 cm with an error 0.02 cm. The percentage error in its area is

$\begin {array} {1 1} (a)\;\frac{1}{7} & \quad (b)\;\frac{1}{28} \\ (c)\;\frac{1}{14} & \quad (d)\;\frac{1}{56} \end {array}$

$(c)\;\frac{1}{14}$