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What volume of hydrogen gas at 273K and 1atm pressure will be consumed in obtaining 21.6g of element boron (at.mass=0.8) from the reduction of boron trichloride with hydrogen ?

$(a)\;44.8L\qquad(b)\;22.4L\qquad(c)\;89.6L\qquad(d)\;67.2L$

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$2BCl_3+3H_2\rightarrow 2B+6HCl$
$2\times 10.8g$ Boron =$3\times 22.42H_2$
$\therefore 21.6g$ Boron =$\large\frac{3\times 22.4\times 21.6}{2\times 10.8}$
$\Rightarrow 67.2L$
Hence (d) is the correct answer.
answered Oct 28, 2013 by sreemathi.v
 

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