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25ml of a solution of barium hydroxide titration with 0.1molar solution of hydro-chloric acid gave a titre value of 35ml.The molarity of barium hydroxide is

$(a)\;0.28\qquad(b)\;0.35\qquad(c)\;0.07\qquad(d)\;0.14$

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$Ba(OH)_2+2HCl\rightarrow BaCl_2+2H_2O$
$M_1V_1X_1\rightarrow M_2V_2X_2$
($x_1$ & $x_2$ =v.f)
$M_1\times 25\times 2=0.1\times 35\times 1$
$\therefore M_1=\large\frac{3.5}{50}$
$\Rightarrow 0.07$
Hence (c) is the correct answer.
answered Oct 28, 2013 by sreemathi.v
 

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