logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

$6.02\times 10^{20}$ molecules of urea are present in 100ml solution.The concentration of urea solution is

$\begin{array}{1 1}(a)\;0.1 m&(b)\;0.01m\\(c)\;0.02m&(d)\;0.001m\end{array}$

Can you answer this question?
 
 

1 Answer

0 votes
$M=\large\frac{Moles\;of\; urea}{V\;in\;litre}$
$\;\;\;=\large\frac{6.02\times 10^{20}\times 1000}{6.023\times 10^{23}\times 100}$
$\;\;\;=10^{-2}m$
Hence (b) is the correct answer.
answered Oct 28, 2013 by sreemathi.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...