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To neutralize completely 20ml of 0.1m aqueous solution of phosphorus $(H_3PO_3)$ acid the volume of 0.1m aqueous KOH solution required is

$\begin{array}{1 1}(a)\;60ml&(b)\;20ml\\(c)\;40ml&(d)\;10ml\end{array}$

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$H_3PO_3+2KOH\rightarrow K_2HPO_3+2H_2O$
$M_1V_1X_1=M_2V_2X_2$
$0.1\times 20\times 2=0.1\times V_2\times 1$
$V_2=40ml$
Hence (c) is the correct answer.
answered Oct 28, 2013 by sreemathi.v
 

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