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Amount of oxygen required for combustion of 1kg of a mixture of butane and isobutane is

$\begin{array}{1 1}(a)\;1.8kg&(b)\;2.7kg\\(c)\;4.5kg&(d)\;3.58kg\end{array}$

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Butane and isobutane have same molecular formula $C_4H_{10}$
$C_4H_{10}+\large\frac{13}{2}$$O_2\rightarrow 4CO_2+5H_2O$
58g $C_4H_{10}$ requires $O_2=\large\frac{13}{2}$$\times 32g$
$\therefore 1000g C_4H_{10}$ requires $O_2=\large\frac{13\times 32\times 1000}{2\times 58}$
$\Rightarrow 358.62g$
Or $3.586kg$
Hence (d) is the correct option.
answered Oct 28, 2013 by sreemathi.v

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