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$\int \large \frac{\sin x+ 8 \cos x}{4 \sin x+6 \cos x}$$ dx$ is equal to

\[\begin {array} {1 1} (a)\;x+\frac{1}{2} \log (4 \sin x+ 6 \cos x)+c & \quad (b)\;2x+\log (2 \sin x+3 \cos x)+c \\ (c)\;x+2 \log (2\sin x +3 \cos x)+c & \quad (d)\;\frac{1}{2}\log (4 \sin x+6 \cos x)+c \end {array}\]

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$(a)\;x+\frac{1}{2} \log (4 \sin x+ 6 \cos x)+c$
answered Nov 7, 2013 by pady_1
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