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The solution of $\large\frac{dy}{dx}$$+1=e^{x+y}$ is

\[\begin {array} {1 1} (a)\;e^{-(x+y)}+x+c=0 & \quad (b)\;e^{-(x+y)}-x+c=0 \\ (c)\;e^{x+y}+x+c=0 & \quad (d)\;e^{x+y}-x+c=0 \end {array}\]
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1 Answer

$(a)\;e^{-(x+y)}+x+c=0$
answered Nov 7, 2013 by pady_1
 
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