Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The molality of 1M solution of NaCl (specific gravity $1.0585g/ml$) is :


Can you answer this question?

1 Answer

0 votes
Weight of solvent =weight of solution-weight of Nacl
$\Rightarrow 1.0585\times 1000-58.5$
$\Rightarrow 1058.5-58.5=1000g=1kg$
$\therefore m=1/1$
$\Rightarrow 1$
Hence (b) is the correct answer.
answered Oct 28, 2013 by sreemathi.v
edited Oct 28, 2013 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App