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The molality of 1M solution of NaCl (specific gravity $1.0585g/ml$) is :


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Weight of solvent =weight of solution-weight of Nacl
$\Rightarrow 1.0585\times 1000-58.5$
$\Rightarrow 1058.5-58.5=1000g=1kg$
$\therefore m=1/1$
$\Rightarrow 1$
Hence (b) is the correct answer.
answered Oct 28, 2013 by sreemathi.v
edited Oct 28, 2013 by sreemathi.v

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