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The molality of 1 litre solution with $X\%$ by weight $H_2SO_4$ is equal to 9.The weight of the solvent present in the solution is 910g.The value of $X$ :


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$m=\large\frac{a\times 1000}{98\times 910}$
$\Rightarrow 9$
$\%$ by weight =80.26g
$\qquad\quad\quad\;\; =X$
Hence (b) is the correct option.
answered Oct 29, 2013 by sreemathi.v

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