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The no of moles of $KMnO_4$ that will be needed to react with one mole of sulphite ion in acidic solution

$(a)\;\large\frac{2}{5}$$\qquad(b)\;\large\frac{3}{5}$$\qquad(c)\;\large\frac{4}{5}\qquad$$(d)\;\large\frac{1}{2}$

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$5SO_3^{2-}+2MnO_4^-+6H^+\rightarrow 2Mn^{2+}+5SO_4^{2-}+3H_2O$
$\therefore$ 1 mole of $SO_3^{2-}$ required $\large\frac{2}{5}$ mole of $KMnO_4$
Hence (a) is the correct answer.
answered Oct 29, 2013 by sreemathi.v
 

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